Question

Find the area of the minor segment of a circle of radius 42cm, if length of the corresponding
arc is 44cm.

Answer 1

Answer: plzz mark as brainliest

Step-by-step explanation:

Length of arc = θ/180 * πr

44 = θ /180 * 22/7 * 42

θ = 60°

Area of minor segment = θ/360 * πr²

                                      = 60/360 * 22/7 * 42* 42

                                       = 924 cm²

Answer 2

Hola ❣️

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Arc length subtended by angle Ѳ

$\implies \frac{ \theta}{180 {}^{o} } \times 2\pi r = 44 \\ \\ \implies \frac{ \theta}{180 {}^{o} } \times 2\pi \times 42 = 44 \\ \\ \text{Angle} \: \theta = \frac{44 \times 180}{2\pi \times 42} \\ \\ \text{Angle} \: \theta =60\degree$

Now, area of minor segment ;

$\implies \frac{ \theta}{360 {}^{o} } \times \pi r {}^{2} \\ \\ \implies \frac{60}{360} \times \pi \times 42 \times 42 \\ \\ = \boxed{ \bold{924 \: cm {}^{2} }}$

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Thanks !!