Find the area of the minor segment of a circle of radius 28cm if length of the corresponding arc APB is 44cm.
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109
Solution:-
Area of the segment = Area of the sector - Area of the triangle
Area of the sector = θ/360°πr²
Area of the triangle = 1/2*AB*sinθ
Here, the length of the arc = 44 cm
Radius = 28 cm
First, we have to find out the angle θ by using the formula of length of the arc.
Then,
44 = θ/360°2πr
θ = (44*7*360)/(2*28*22)
θ = 90°
Now,
Area of the sector = 90/360*22/7*28*28
Area of the sector = 616 sq cm
Area of the triangle = 1/2*28*28*sin90
= 1/2*28*28*1
Area of the triangle = 392 sq cm
Area of the segment = 616 - 392
Area of the sector = 224 sq cm
Answer.
Area of the segment = Area of the sector - Area of the triangle
Area of the sector = θ/360°πr²
Area of the triangle = 1/2*AB*sinθ
Here, the length of the arc = 44 cm
Radius = 28 cm
First, we have to find out the angle θ by using the formula of length of the arc.
Then,
44 = θ/360°2πr
θ = (44*7*360)/(2*28*22)
θ = 90°
Now,
Area of the sector = 90/360*22/7*28*28
Area of the sector = 616 sq cm
Area of the triangle = 1/2*28*28*sin90
= 1/2*28*28*1
Area of the triangle = 392 sq cm
Area of the segment = 616 - 392
Area of the sector = 224 sq cm
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