Math, asked by AllisonT101, 9 months ago

Find the area of the oblique triangle rounded to the nearest hundredth. (just the number no units).

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Answers

Answered by Anonymous
0

Answer:

2,288.87 m²

Step-by-step explanation:

A = \frac{1}{2} × a × b × sin C

A = \frac{1}{2} × 52 × 90 × sin102° ≈ 2,288.87 m²

Answered by sonuvuce
0

The area of the oblique triangle rounded to the nearest hundredth is 2289

Step-by-step explanation:

If two sides of a triangle is a and b and the angle between them is C

Then, the area of the triangle is given by

\Delta=\frac{1}{2}ab\sin C

Here,

a = 90 m

b = 52 m

∠C = `102°

Therefore, the area of the triangle is

\Delta=\frac{1}{2}\times 90\times 52\times\sin 102^\circ

\implies \Delta=45\times52\times 0.978

\implies\Delta=2288.87

Find the area of the oblique triangle rounded to the nearest hundredth is 2289

Hope this answer is helpful.

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