find the area of the parabola y square = 4ax and x =a
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Answer:
Required area = area of curve PSMNRQP
=2 area of curve PSRQP
=2∫a4a4axdx
=4a⎣⎢⎢⎢⎢⎡23x23⎦⎥⎥⎥⎥⎤a4a=38a[(4a)23−a23]
=38a[8a23−a23)=356a2
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