Question

Find the area of the parallelogram abcd if ab =20 cm, bc =12 cm and ac =24 cm using heron's formula

Answer 1

in parallelogram ABCD connect AC
Now we have two triangles ABC and ADC
Given AB = 20cm
BC = 12cm
AC = 24cm
*Area of triangle ABC is
s = ab+ BC+Ac/2
=20+12+24/2
=56/2
=28cm.
Area = √s(s-ab)(s-bc)(s-ac)
=√28(28-20)(28-12)(28-24)
=√28(8)(16)(4)
=√144336
=379.90
*Area of triangle ADC
s = ad+DC+Ac/2
=28cm
Area = 379.90
the area of parallelogram ABCD is 379.90+379.90 = 759.8
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