Question

find the area of the parallelogram whose adjacent sides are 2i-3j, 3i-k​

Answer 1

Answer:

Answer

Consider the given vectors

a

=2

i

^

−3

j

^

b

=3

i

^

−

j

^

Let the area of parallelogram is

∣

a

×

b

∣

Therefore,

a

×

b

=

∣

∣

∣

∣

∣

∣

∣

∣

i

^

2

3

j

^

−3

−1

k

^

0

0

∣

∣

∣

∣

∣

∣

∣

∣

=7

k

^

Now,

∣

a

×

b

∣=

7

2

=7

Hence the area of parallelogram is 7 sq. units