Question

Find the area of the parallelogram whose sides are represented by 2hati + 4hatj - 6hatk and hati +2hatk.

Answer 1

the area of parallelogram is 13.4 approx units.....

hope it helps u...✌✌

Answer 2

Side of the parallelogram are a=2hati+4hatj-6hatk and b=hati+2hatj then the area is 13.41 Units.

1. Here we know that the area of parallelogram with given sides a and b will be equal to magnitude of cross product of a & b.

2. Now cross product of  a and b can be calculated by determinant method.

3. From calculations the cross product comes out to be 12hati+6hatj.

4. Now the magnitude of the cross product =$\sqrt{12^{2} +6^{2} }$

                                                                        =$\sqrt{144+36}$

                                                                        =$\sqrt{180}$

                                                                        = 13.41. units