Question

Find the area of the parallelogram whose sides are 3x+4y+5=0 , 3x+4y-2=0,2x+3y+1=0 and 2x+3y-7=0.

Answer 1

Answer:

Step-by-step explanation:

Find the area of the parallelogram whose sides are 3x+4y+5=0 , 3x+4y-2=0,2x+3y+1=0 and 2x+3y-7=0.

Given sides are

3 x + 4 y + 5 = 0

3 x + 4 y – 2 =0

2 x + 3 y + 1 = 0

2 x + 3 y – 7 = 0

Area of parallelogram formed by 1, 2, 3, 4 are

I (c1 – c2)(d1 – d2) / a1b2 – a2b1 I

I (5 + 2)(1 + 7) / 3(3) – 2(4)I

I7 x 8 / 9 – 8I

= 56 sq units

Answer 2

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