Question

Find the area of the parallelogram with base 3.5 cm and altitude 4.5 cm

Please answer the question real quick!
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Answer 1

Answer:

15.75cm^2

Step-by-step explanation:

area=base×height (altitude)

=3.5×4.5

=15.75cm^2

MARK IT AS BRAINLIEST.

Answer 2

Given : The Base of Parallelogram is 3.5 cm and Altitude is 4.5 cm .

Exigency To Find : Area of Parallelogram.

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❍ Formula For Area of Parallelogram is given by :

$\dag\:\: \boxed {\sf{ Area _{(Parallelogram)} = \bigg( b \times h \bigg) \:sq.units}}$

Where ,

• b is the Base of Parallelogram & h is the Height of Parallelogram .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$:\implies \sf{ Area_{(Parallelogram)} = 3.5 \times 4.5 }$

$:\implies \sf{ Area_{(Parallelogram)} = 15.75 \:cm^2 }$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Area \:of\:Parallelogram \:is\:\bf{15.75\: cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

• $\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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