Question

find the area of the parallogram whose sides are 5cm,4cm,5cm,4cm and diagonal 8cm. and height 2cm.
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Answer 1

Answer:

Answer

In quadrilateral ABCD,

AB=3 cm,BC=4 cm,CD=2 cm,DA=5 cm and ∠ABC=90

0

Area of ABCD = Area of ΔABC+ Area of ΔACD

In ΔABC,∠B=90

0

∴ Area of Δ ABC =

2

1

×AB×BC=

2

1

×3×4=6cm

2

In ΔACD,s=

2

2+5+5

=6m

Applying Heron's formula,

Area of ΔACD =

S(S−a)(S−b)(S−c)

=

6(6−5)(6−5)(6−2)

=

6(1)(1)(4)

=

24

Hence, Area of □ABCD=(6+

24

)cm

2

So, option C is correct.

Answer 2

hope it will help you buddy