Find the area of the path 5 m wide which runs around a rectangular park of dimensions 60m by 45 m. Find the cost of maintaining the flower bed at the rate of rupees 9per m square.
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Answer:
Given inner side of square park, s=100 cm
Area of inner square =
100² =10000 cm²
width of path,w=5 cm
Outer side of square =100+5+5=110 cm
Area of outer square =
110² = 12100 cm²
Area of path =12100−10000=2100 cm²
Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500
∴ Cost of cementing a 2100 cm²
path =Rs. 52500
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