Question

find the area of the paths in the following figure.​

Answer 1

Figure1

Length of outer field=219+2(2)=219×4=876m

Breadth of outer field=120+2(2)=120×4=480m

Area of outer field=2(l+b)=2(876+480)=2×1356=2712m²

Length of inner field=129m

Breadth of inner field=120m

Area of inner field=2(l+b)=2(129+120)=2×339=778m²

Area of path=Area of outer field-Area of inner field=2712-778m²=1934m²

Figure2

Length of outer field=12m

Breadth of outer field=9m

Area of outer field=2(12+9)=2×21=42m²

Length of inner field=12-2(1.5)=12-3=9m

Breadth of inner field=9-2(1.5)=9-3=6m

Area of inner field=2(9+6)=2×15=30m²

Area of path=Area of outer field-Area of inner field=42-30m²=12m²

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