find the area of the Pentagon ABCD,if AD=8cm,AH=6cm,AG=4cm,AF=3cm,BF=2cm,CH=3cm and EG=2.5cm.
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Answer:
23.5 cm^2
Step-by-step explanation:
area of Triangle AED = 1/2 base × height
= 1/2 × Ad × EG
= 1/2 × 8 × 2.5
= 2.5×4
= 10 cm^2
Fh = Ah - Af = 6-3 = 3cm
Area of Trapezium BFCH = 1/2(sum of parallel sides) ×h
= 1/2 × (BF + CH) × FH
= 1/2 × (2 + 3) × 3
= 15/2 = 7.5 cm^2
Area of triangle ABF = 1/2 × BF × AF
= 1/2 × 2 × 3 = 3cm^2
DH = AD - AH = 8 - 6 = 2cm
Area of triangle CHD = 1/2 CH × DH
1/2 × 3 × 2 = 3cm^2
Area of Pentagon ABCD = ar(AED) + ar(ABF) + ar(CHD) + ar(BFCH) = 10+ 7.5+ 3+3 = 23.5 cm^2
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