Question

Find the area of the plot of land which is in the form of a quadrilateral with one diagonal of length 60 m and lengths of perpendiculars drawn from the opposite vertices on this diagonal are 38m and 22 m respectively.

Answer 1

*Refer the attachment.

Answer 2

Step-by-step explanation:

$\huge\tt\underline\green{QuestioN}:-$

Find the area of the plot of land which is in the form of a quadrilateral with one diagonal of length 60 m and lengths of perpendiculars drawn from the opposite vertices on this diagonal are 38m and 22 m respectively.

$\huge \tt\underline\red{TO\: FIND: - }$

Area of quadrilateral ❓️

$\huge \tt\underline{\text{A} \blue{N} \orange{S} \pink{W} \green{E} \red{R}} :) :)$

We know that the area of a quadrilateral is equal to the product of one diagonal and half the sum of perpendiculars drawn on it from other two vertices.

$\tt{⟹Area \: of \: a \: quadrilateral =} \\ \tt {21×diagonal×( {p}^{2} + {p}^{2} )}$

where, p1 and p2 are two perpendiculars drawn from opposite vertices$$

Given, length of one diagonal is 60m and the perpendiculars from the other two vertices are 38m and 22m, respectively.

$\tt{⟹Area \: of \: the \: quadrilateral =21×60×(38+22) {m}^{2} } \\ \tt{ =1800 {m}^{2} }$

Hope it helpful...☃️⚡️

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