Question

find the area of the polygon 12 cm 10 cm 18 cm​

Answer 1

Answer:

AD=18cm,AQ=14cm,AN=8cm,AM=4cm

QD=AD−AQ=18cm−14cm=4cm

NQ=AQ−AN=14cm−8cm=6cm

PD=AD−AP=18cm−12cm=6cm

MP=AP−PM=12cm−4cm=8cm

Area of △AMF=

2

1

×5cm×4cm=10cm

2

Area of △EPD=

2

1

×6cm×6cm=18cm

2

Area of △QCD=

2

1

×4cm×4cm=8cm

2

Area of BCQN=

2

1

×(5+4)cm×6cm=27cm

2

Area of EMFQ=

2

1

×(5+6)cm×10cm=55cm

2

Area of polygon ABCDEF=Area of △AMF+Area of △EPD+Area of △QCD+Area of BCQN+Area of EMFQ=(10+18+8+27+55)cm

2

=118cm

2

Answer 2

Answer:

Summary: It is given that in a given triangle two sides are 18cm and 10cm and the perimeter is 42cm. We have found its area equal to 21√11 cm2.