Question

Find the area of the polygon A and B inside the rectangle is given.​

Answer 1

Answer:

150cm^2

Step-by-step explanation:

lets break up the figures, starting with A.

A can be further broken into 2 shapes,

• one a square, say A1, with side 10x10 cm (since its given and one side is 15 - 5 cm)

• and another, say A2, as a rectangle with sides 10x5 (given)

so the area of A will be-

=> ar(A1) + ar (A2)

=> (s x s) + (l x b)

=> (10x10) + (10x5)

=> 100 + 50 = 150$cm^2$

similarly, we find that B is also made of the same shapes with B1 a square with dimensions 10x10 and B2 as a rectangle with 10x5.

so similarly, area of B-

=> ar(B1) + ar (B2)

=> (s x s) + (l x b)

=> (10x10) + (10x5)

=> 100 + 50 = 150$cm^2$

 

Therefore, The areas of both A and B is the same, and measures 150cm^2 each.

Answer 2

Step-by-step explanation:

Solution:

By observing the figure given area of A = area of B

Now Area of A= ½ of outer rectangle

$\[ \begin{array}{l} \rm= \dfrac{1}{2} \times 20 \times 15 \\ \\ \rm=150 \end{array} \]$

Hence area of polygon A and B are 150 sq.cm each.