Question

Find the area of the polygon ABCDEF :

Answer 1

Answer

hope this will help you

Answer 2

Area of Polygon is $4700\ cm^{2}$

Step-by-step explanation:

Given,

Find the area of polygon where,

$FP=10\ cm,FQ=20\ cm,FR=50\ cm,FS=60\ cm\ and\ FC=100cm$

∴ $QS=(FS-FQ)=(60-20)=40\ cm$,$SC=(FC-FS)=(100-60)=40\ cm$,$RC=(FC-FR)=(100-50)=50\ cm$ and $PQ=(FQ-FP)=(20-100)=10\ cm$

∴ Area of $\triangle EFP=\frac{1}{2}\times FP\times EF$

                                    $=\frac{1}{2}\times 10\times 40=200\ cm^{2}$

And Area of $\triangle FQA=\frac{1}{2}\times FQ\times QA$

                                          $=\frac{1}{2}\times 20\times 20=200\ cm^{2}$

And Area of $\triangle BCS=\frac{1}{2}\times CS\times BS$

                                          $=\frac{1}{2}\times 40\times 10=200\ cm^{2}$

And Area of $\triangle CDR=\frac{1}{2}\times RC\times DR$

                                          $=\frac{1}{2}\times 50\times 60=1500\ cm^{2}$

And Area of $PSDE=\frac{(PE+DR)}{2}\times (FR-FQ)$

                             $=\frac{(40+60)}{2}\times (60-20)=\frac{100\times 40}{2}=2000\ cm^{2}$

Also Area of $ABSQ=\frac{(AQ+BS)}{2}\times (FS-FQ)$

                               $=\frac{(20+10)}{2}\times (60-20)=\frac{30\times 40}{2}=600\ cm^{2}$

Sum of all areas$=(200+200+200+1500+2000+600)=4700\ cm^{2}$

So, Area of Polygon is $4700\ cm^{2}$