Math, asked by lavkushsingh87372, 6 months ago

find the area of the polygon as per dimensions given below​

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Answered by akhauriatharva
0

Answer: We can divide this figure into three parts...

First is the square with each side as 2m, second is the rectangle with 4m and 2m, third is the rectangle with 6m and 2m.

Step-by-step explanation:Area of first rectangle (square) (remember that square is also a rectangle) = 2*2 = 4 m^2

Area of second rectangle = 4*2 = 8 m^2

Area of third rectangle = 6*2 = 12 m^2

Adding all the areas, we have -----

4 m^2 + 8 m^2 + 12 m^2

= 24 m^2....

Answered by davinderkaur47865s
0

Answer:

36 cm²

Step-by-step explanation:

area of polygon=area of square+area of 1st rectangle+area of 2nd rectangle

area of square

side of square= 2cm

area of square=side×side

=2×2

=4cm²

area of 1st rectangle

length =6cm

breadth=2cm

area of rectangle =length×breadth

=6×2

=12cm²

area of 2nd rectangle

length =10cm

breadth=2cm

area of rectangle =length×breadth

=10×2

=20cm²

area of polygon=area of square+area of 1st rectangle+area of 2nd rectangle

=4+12+20

=36cm²

therefore,area of polygon is 36cm²

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