find the area of the polygon given in the adjoining figure
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area of the polygon = ar(AEF) + ar(EDHF) + ar(DHC) + ar(ABC
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Mensuration,
We have
Polygon ABCDE
Have to find the area of the polygon.
Here given that
AC = 60 m
BG = 16 m
AF = 16 m
So FH will be = (46 - 16) m = 30 m
and HC will be = (60 - 46) m = 14 m
FE = 24 m
also,DH = 14 m
Now,
Area of the polygon = area of ∆ABC + area of ∆CHD + area of ∆AFE + area of trapezium DEFH.
= [(½ × 60 × 16) + (½ × 14 × 14) + (½ × 16 × 24) + {½ × 30 × (24 + 14)}] m²
= (480 + 98 + 192 + 570) m²
= 1340 m²
So the area of the polygon is 1340 m²
That's it
Hope it helped ❤(ӦvӦ。)
We have
Polygon ABCDE
Have to find the area of the polygon.
Here given that
AC = 60 m
BG = 16 m
AF = 16 m
So FH will be = (46 - 16) m = 30 m
and HC will be = (60 - 46) m = 14 m
FE = 24 m
also,DH = 14 m
Now,
Area of the polygon = area of ∆ABC + area of ∆CHD + area of ∆AFE + area of trapezium DEFH.
= [(½ × 60 × 16) + (½ × 14 × 14) + (½ × 16 × 24) + {½ × 30 × (24 + 14)}] m²
= (480 + 98 + 192 + 570) m²
= 1340 m²
So the area of the polygon is 1340 m²
That's it
Hope it helped ❤(ӦvӦ。)
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