Question

find the area of the polygons ​

Answer 1

Answer:

$\huge\mathfrak\red{holamate}$

Area of Ist traingle

base = 30cm

height = 12 cm

Area of ∆= 1/2×base × height

= 1/2×30×12

=180 cm sq.

Area of IInd triangle

base = 30 cm

height = 20-12= 8 cm

Area of ∆= 1/2 × 30×8

=120 cm sq.

Area of polygon

Area of Ist triangle+ Area of IInd traingle

=(180+120)cm sq.

=300cm sq.

$\huge\mathfrak\pink{thanks}$

Answer 2

YᎾUℛ ᎯℕЅᏇℰℛ

300 cm²

⬇️Explanation ⬇️

Firstly check the attachment

In ∆ ABC

Height = 12 cm

Base = 20 cm

Area of triangle = ½ x B x H

$\frac{1}{2} \times 20 \times 12 \\ \\ = 120 \: {cm}^{2}$

Now in ∆ ADC

Height = 18 cm

Base = 20 cm

Area = ½ x B x H

$\frac{1}{2} \times 20 \times 18 \\ \\ = 180 \: {cm}^{2}$

Now add both areas

180 + 120 = 300 cm²

✌️Hope this helps you ✌️

✨Pℒℤ ℳᎯℛᏦ ℐᏆ ᎯЅ ℬℛᎯℐℕℒℐℰЅᏆ ᎯℕЅᏇℰℛ✨