Find the area of the PQRS
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join SQ
then
area of parallelogram SQDC = base x height
18x4=72
area of triangle SPQ= 1/2of 72 (= 36 triangle and parallelogram on same base the area of traingle 1/2 are of parallelogram)
similarly
Area SABQ = 1/2 OF RQS = 36
then area of PQRS = 72
then
area of parallelogram SQDC = base x height
18x4=72
area of triangle SPQ= 1/2of 72 (= 36 triangle and parallelogram on same base the area of traingle 1/2 are of parallelogram)
similarly
Area SABQ = 1/2 OF RQS = 36
then area of PQRS = 72
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how IIgram SQCD
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