Question

Find the area of the quadrant of a circle of a circle circumference is 22 cm. What is the surface area of the solid hemisphere of radius r cm

Answer 1

Step-by-step explanation:

For a Circle ,

Circumference = 22 cm

2πr = 22 cm

2×22/7 × r = 22 cm

2r/7 = 1 cm

2r = 7 cm

r = 3.5 cm

area of a quadrant of a Circle =πr²/4

1/4 ( 22/7 * 7/2 * 7/2 )

22*7*7/4*7*4

11*7/2*4 = 77/8 = 9.625 cm²

Surface area of a Solid hemisphere =>

TSA = 3πr² , CSA = 2πr²

Answer 2

Answer:

area of the quadrant=38.5

surface area of the solid hemisphere of radius r cm=102.6cm2

Step-by-step explanation:

circumference is 22 cm.

2πr=22

r=7cm

area of quadrant=1/4(πr^2)

=1/4(22/7)(49)

=38.5cm2

surface area of the solid hemisphere of radius r cm=2/3πr2

102.6cm2