find the area of the quadrilateral
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It is given in question that,
ABCD is a quadrilateral, where
AC =22cm
BM = 3cm
DN = 3cm
BM is perpendicular to AC & DN is perpendicular to AC
Therefore ,
Area of (ABCD) = Area (ABC) + area (ADC)
= ar(ABCD) = ½×(3×22) + ½×(3×22)
= ½×66 + ½×66
= (33+33)cm²
= 66cm² Ans....
Hope it helps.....:-)
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