Question

Find the area of the quadrilateral....​

Answer 1

Step-by-step explanation:

∆ ADC + ∆ABC = Quadrilateral ADCB

AREA OF ∆ADC = ½× Base × Height

$\frac{1}{2 } \times 75 \times 40$

1500

Area of ∆ABC = ½× Base × Height

$\frac{1}{2 } \times 75 \times 50$

$1875$

Therefore, Area of Quadrilateral ADCB

= 1500 + 1875 = 3375m²

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Answer 2

If the diagonal and the length of the perpendiculars from the vertices are given, then the area of the quadrilateral is calculated as: Area of quadrilateral = (½) × diagonal length × sum of the length of the perpendiculars drawn from the remaining two vertices.

step by step explaination:

∆ ADC + ∆ABC = Quadrilateral ADCB

AREA OF ∆ADC = ½× Base × Height

1

---×75×40

2

=1500

Area of ∆ABC = ½× Base × Height

\frac{1}{2 } \times 75 \times 50

1

__ ×75×50

2

18751875

Therefore, Area of Quadrilateral ADCB

= 1500 + 1875 = 3375m²

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