Find the area of the quadrilateral ABCD, given in the adjoining
figure in which AB = 14 cm, BC = 78 cm, CD = 112 cm,
BD = 50 cm and DA = 48 cm.
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Answer:
By using heron's formula
In ΔABD
S=14+50+48=112/2=56
√s(s-a)(s-b)(s-c)
√56(56-14)(56-50)(56-48)
√56*42*6*8
√2*2*2*7*7*2*3*2*3*2*2*2
2*2*7*3*2*2=336cm²
Now, in ΔBDC
S=50+78+112=240/2=120
√120(120-50)(120-78)(120-112)
√120*70*42*8
√2*2*3*2*5*7*2*5*2*3*7*2*2*2
2*2*5*3*7*2*2=1680cm²
Ar(ΔABD)+Ar(ΔBDC)
(336+1680)cm²=2016cm²
Step-by-step explanation:
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