Question

Find the area of the quadrilateral ABCD given in the
adjoining figure.​

Answer 1

Answer:

Assuming ∠ABC = 90, area = 79.79 cm²

Step-by-step explanation:

Area of ABCD = area of ΔADC + area of ΔABC

Area of ABC = 0.5 × base × height

= 0.5 × 7 × 15 = 52.5 cm²

Now, AC = √(AB²+BC²) Pythagoras theorem

AC = √(7²+15²)

AC = 16.55 cm (It cannot be 9 as shown in the image, the hypotenuse is the longest side)

Use Heron's formula to find the area of Δ ADC

Area = √(s×(s-a)×(s-b)×(s-c))

where s = (a+b+c)/2

Putting the value of a = 6, b = 12 and c = 16.55

We get the area = 27.29 cm²

Therefore, area of quad = 52.5 + 27.29 = 79.79 cm²