Question

Find the area of the quadrilateral ABCD.
Here, AC=22 cm, BM-3 cm,
18 cm and is a DN=3 cm, and
BM perpendicular to AC, DN perpendicular to AC.​

Answer 1

Answer:

231

Step-by-step explanation:

Area of triangle DAC = 1/2 × 22 × 18= 198

Area of triangle ABC= 1/2 × 22 × 3 = 33

Area of the quadrilateral = Area of triangle DAC + Area of triangle ABC

= 198 + 33

= 231

Answer 2

Answer:

66cm^2 is the answer please mark me as brainliest

Step-by-step explanation:

To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Area of ΔADC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Then,

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 33 + 33

= 66 cm2