Find the area of the quadrilateral ABCD here ac=22 cm, bm=3cm,dn=3cm and BM is perpendicular to AC, DN is perpendicular to AC.
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14
area of quadrilateral=1/2d(h1+h2)
1/2×22(3+3)
1/2×22×6
11×6=66cm.sq
1/2×22(3+3)
1/2×22×6
11×6=66cm.sq
Answered by
10
area of triangle ABC 1/2*22*3= 33cm ^2
area of triangle ADC 1/2*22*3=33cm^2
area of quadrilateral ABCD =33+33=66 cm ^2
area of triangle ADC 1/2*22*3=33cm^2
area of quadrilateral ABCD =33+33=66 cm ^2
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