Find the area of the quadrilateral ABCD
Here,AC = 22cm, BM =3cm
DN = 3, and
BM is perpendicular to AC is perpendicular AC
Attachments:

Answers
Answered by
2
Answer:
66 cm²
Step-by-step explanation:
Here,
AC = 22cm, BM =3cm, DN = 3cm, and BM is perpendicular to AC and DN is perpendicular AC.
Now,
Area of triangle ABC = 1/2 × AC × BM
=1/2 × 22 × 3
= 33 cm²
and,
Area of triangle ACD = 1/2 × AC × DN
= 1/2 × 22 × 3
= 33 cm²
So, area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD
= 33 cm² + 33 cm²
= 66 cm²
Answered by
1
Answer:
hi bro this is very easy 66 CM 2 is
your answer
Similar questions