Question

Find the area of the quadrilateral ABCD here AC = 80 cm, BM = 4 cm, DN = 6 cm and BM ⊥AC and DN ⊥AC. *

Answer 1

Answer:

Area of \Delta ABC=\frac{1}{2}\times b\times h=\frac{1}{2}\times22\times3=33cm^2ΔABC=

2

1

×b×h=

2

1

×22×3=33cm

2

Area\ of\ \Delta ADC=\frac{1}{2}\times22\times3=33cm^2Area of ΔADC=

2

1

×22×3=33cm

2

Area of the quadrilateral ABCD

= Area of \Delta ABCΔABC+Area of \Delta ADCΔADC

=33cm^2+33cm^2=66cm^2=33cm

2

+33cm

2

=66cm

2

Hence, the required area= 66cm^266cm

2