Question

Find the area of the quadrilateral ABCD if a diagonal AC= 22cm and the corresponding altitudes from opposite vertices B and D are BM=3cm and DN= 3cm.​

Answer 1

Answer:

66cm²

Step-by-step explanation:

As mentioned it is a General Quadrilateral

The area of a General Quadrilateral is 1/2 * Diagonal * (height 1 + height2)

In this case, Diagonal = AC, Height 1 = DN, Height2 = MB

So, the area of This general Quadrilateral is 1/2* AC * (DN + MB)

From the image we know AC = 22cm, DN= 3cm, MB=3cm

So the area of this general quadrilateral is 1/2* 22 *(3+3)

⇒11*6

66cm²

Hope it helps...