Question

Find the area of the quadrilateral ABCD in which AB = 9 cm, BC = 40 cm, DC = 28 cm,

AD = 15 cm, diagonal AC = 41 cm. and ∆ABC = 90°.

can any one solve on page nd share the ans please.​

Answer 1

Answer:306

Step-by-step explanation:

let firstly we find the area of the  triangle ABC

S=40*9/2=180 - Because of it is right triangle

secondly we can find the area of the triangle ACD by Heron's formula

S^2=p*(p-a)*(p-b)*(p-c)  where a, b,c are the sides of the triangle and p=(a+b+c)/2

p=(28+15+41)/2=42

S^2=42*14*27*1=126^2

S=126

So the area of the quadrilateral is the sum of these triangles ABC and ACD

S=126+180=306