Question

find the area of the quadrilateral ABCD in which ab is equals to 4 BC is equals to 6 CD = 5 , DA= 5 and AC = 6 CM​

Answer 1

Step-by-step explanation:

Area of ΔABC

=

s(s−a)(s−b)(s−c)

=

15(15−9)(15−8)(15−13)

=

6(1)(2)(3)

=

36

=6

⇒For area of ΔADC,

⇒2S=5+4+5

⇒ S=7cm

⇒Area of ΔADC

=

7(7−5)(7−5)(7−4)

=

7×2×2×3

=2

21

=9.16m

2