Find the area of the quadrilateral ABCD in which
by a
AB = 5 cm, BC = 4.5 cm, CD = 3.5 cm, DA = 4 cm and AC = 6.5 cm
Answers
Find the area of the quadrilateral ABCD in which
by a
AB = 5 cm, BC = 4.5 cm, CD = 3.5 cm, DA = 4 cm and AC = 6.5 cm
AB = 5 cm,
BC = 4.5 cm,
CD = 3.5 cm,
DA = 4 cm and
AC = 6.5 cm
A(ABCD) = 17.285 cm?
Step-by-step explanation:
Heron formula
A = vs(s - a)(s - b)(s - c)
s= (a + b + c)/2
a;b; c= the sides of the triangle
.
A(ABCD) = A(ABC) + A(ACD)
1. A(ABC) = vs(s - AB)(S - BC)(S - AC)
s= (AB + BC + AC)/2 = (5cm + 4.5cm + 6.5cm)/2 = 16cm/2 = 8 cm
A(ABC) = 1818 - 5)(8 - 4.5)(8 - 6.5)
= V8x3x3.5x1.5
= 7126
= 11.225 cm
2. A(ACD) = vs/S - AC)(s - CD) (S - AD) s=(AC + CD + AD)/2 = (6.5cm + 3.5cm + 4cm)/2 = 14cm/2 = 7 cm A(ACD) = 7717-6.5)(7 - 3.5)(7 - 4)
A(ACD) = Vs(S - AC)(s - CD) (s - AD)
S = (AC + CD + AD)/2 = (6.5cm + 3.5cm + 4cm)/2 = 14cm/2 = 7 cm
A(ACD) = 1717 - 6.5)(7 - 3.5)(7 - 4)
= V7x0.5*3.5*3
= 136.75
= 6.060 cm?
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