Question

find the area of the quadrilateral ABCD where AB=7cm, BC=6cm, CD12cm, DA= 15cm and AC=9cm​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

ANSWER

By applying heron's formula in triangle ABC having the sides 7 cm,6 cm and 9 cm, we have

s=27+6+9=11 cm

Area of triangle =s(s−a)(s−b)(s−c)

=11(11−7)(11−6)(11−9)

=440 cm2

Now, in triangle ADC having sides 15 cm,12 cm and 9 cm, we have

s=215+12+9=18 cm

=18(18−15)(18−12)(18−9)

=54 cm2

There, the area of quadrilateral ABCD=(440+54) cm2