Question

find the area of the quadrilateral ABCD whose diagonal AC is 25 CM long and the lengths of perpendiculars from opposite vertices B and B on AC are BE=3.6cm and DF=2.4 CM. ​

Answer 1

Step-by-step explanation:

area =1/2 × one diagonal × sum of the length of perpendiculars drawn from it on the remaining two vertices

area=1/2 ×25 × (3.6+2.4)

=1/2×25×6

1/2×150

75

so area is 75 Sq unit