Find the area of the quadrilateral field ABCD in which AB=50m BC= 18m , CD= 82m , DA=50m, angle CBD=90°. Please give full steps
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Answer:
HEY MATE
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC= 1/2×3×4
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC= 1/2×3×4= 6
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC= 1/2×3×4= 6Area of △ABC = 6 cm2 ……(2)
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC= 1/2×3×4= 6Area of △ABC = 6 cm2 ……(2)Now, In △CAD,
Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)△ABC is a right-angled triangle which B.Area of △ABC = 1/2 x Base x Height= 1/2×AB×BC= 1/2×3×4= 6Area of △ABC = 6 cm2 ……(2)Now, In △CAD,Sides are given, apply Heron’s Formula.
Perimeter = 2s = AC + CD + DA
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cm
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cms = 7 cm
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cms = 7 cmArea of the △CAD = 9.16 cm2 …(3)
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cms = 7 cmArea of the △CAD = 9.16 cm2 …(3)Using equation (2) and (3) in (1), we get
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cms = 7 cmArea of the △CAD = 9.16 cm2 …(3)Using equation (2) and (3) in (1), we getArea of quadrilateral ABCD = (6 + 9.16) cm2
Perimeter = 2s = AC + CD + DA2s = 5 cm + 4 cm + 5 cm2s = 14 cms = 7 cmArea of the △CAD = 9.16 cm2 …(3)Using equation (2) and (3) in (1), we getArea of quadrilateral ABCD = (6 + 9.16) cm2= 15.16 cm2.
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