Math, asked by mohammedyahirsheikh, 3 months ago

Find the area of the quadrilateral formed by joining the points A(-4,8),B(-4,2),C(6,-7) and D(-6,1) in order.

Answers

Answered by lalitnit
0

Answer:

The sides of quadrilateral

AB = 6

BC = 13.453624

CD = 14.4222051

AD = 7.28010989

Then,

Semi-Perimeter

s= 41.155939/2= 20.5779695

The area of quadrilateral,

A = √(s-a)(s-b)(s-c)(s-d)

A = √(20.58-6)(20.58-13.45)(20.58-14.22)(20.58-7.28)

A = √(14.58*7.13*6.36*13.3)

A = √8,793.37938

A = 93.77 Sq units.

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