find the area of the quadrilateral if the lengths of the diagonals are 18 cm and 32 cm and they bisect each other perpendicularly
Answers
Answered by
10
As the diagonals meet perpendicularly they are rombus.
Area of rombus = 1/2 x d₁x d₂
= 0.5 x 18 x 32
=288 cm²
Hope my answer is helpful to u.
Area of rombus = 1/2 x d₁x d₂
= 0.5 x 18 x 32
=288 cm²
Hope my answer is helpful to u.
Answered by
11
hlo frnd
here ypur answer goes like this
if in an quadrilateral diagonals bisect each other at 90 degrees then its RHOUMBS
and the area od Rhoumbs is 1/2 × d1 × d2
here d1 and d2 are diagonals
let d1 = 18cm
d2 = 32 cm
then area of Rhoumbs = 1/2 × 18 × 32
= 1/2 × 576
= 288cm^2
there fore area of Rhoumbs = 288cm^2
here ypur answer goes like this
if in an quadrilateral diagonals bisect each other at 90 degrees then its RHOUMBS
and the area od Rhoumbs is 1/2 × d1 × d2
here d1 and d2 are diagonals
let d1 = 18cm
d2 = 32 cm
then area of Rhoumbs = 1/2 × 18 × 32
= 1/2 × 576
= 288cm^2
there fore area of Rhoumbs = 288cm^2
Anonymous:
Thanks
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