find the area of the quadrilateral in the following figure AB=14 BD =12 BE =5 CF =4
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Dear Student,
● Answer -
Area = 245.4 sq.cm
◆ Explaination -
# Given -
Four sides of quadrilateral -
a = AB = 13 cm
b = BC = 16 cm
c = CD = 20 cm
d = DA = 5 cm
# Solution -
Semi-perimeter of quadrilateral is calculated by -
s = (a + b + c + d) / 2
s = (13 + 16 + 20 + 5) / 2
s = 27 cm
Area of cyclic quadrilateral is -
Area = √[(s-a)(s-b)(s-c)(s-d)]
Area = √[(27-13)(27-16)(27-10)(27-4)]
Area = √(14 × 11 × 17 × 23)
Area = √60214
Area = 245.4 sq.cm
Hence, area of quadrilateral is 245.4 sq.cm.
Thanks dear.
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