Question

find the area of the quadrilateral whose all four sides are 4 cm diagnol are 7cm and 6cm



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Answer 1

$\bf{\huge{\underline{\boxed{\sf\purple{Answer:\:21\:cm^2}}}}}$

Given :

• A quadrilateral with all 4 sides equal, i.e 4 cm is given.
• Diagonals are : 7 cm and 6 cm

To Find:

• Are of the given quadrilateral

$\huge\underline\green{\tt Solution}$

As stated in the question, All four sides are 4 cm. It means that the quadrilateral is either a rhombus or a square.

Also,

Both the diagonals are unequal. As we know, the diagonals of square are equal. Hence, It's a rhombus!

Now, moving to the question -

→ Area of rhombus = $\dfrac{1}{2} \times diagonal_1 \times diagonal_2$

$= \frac{1}{2} \times 7\times 6 \\\\= \frac{42}{2} \\\\=21\: cm^{2}$

Therefore,

Area of the quadrilateral is 21 cm².

Answer 2

Answer:

21

Step-by-step explanation:

Hence, the quadrilateral is a rhombus

Area of Rhombus is = 1/2x d1 x d2

= 1/2 x 6 x 7

= 1 x 3 x 7

= 27 CM

Here, d1 = diagonal 1

d2 = diagonal 2