Find the area of the quadrilateral whose one diagonal is 20cm long and the perpendiculars to this diagonal from other vertices are of length 9cm and 15cm.
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area of any quadrilateral = 1 /2 ×d( p +p2 )
= 1 /2 ×20 cm ( 15 cm + 9 cm )
= 10cm ×24cm
= 240 square cm.
= 1 /2 ×20 cm ( 15 cm + 9 cm )
= 10cm ×24cm
= 240 square cm.
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