Find the area of the quadrilateral whose sides measure 9 cm, 40 cm,
28 cm and 15 cm, and in which the angle between the first two sides
is a right angle.
Answers
Answered by
1
Answer:
360cm^2
Step-by-step explanation:
area pf quadrilateral=side1×side2×angle between these 2 sides
9×40×sin90=360
Answered by
8
In Quadrilateral ABCD
AB = 9CM
BC = 40CM
CD = 28CM
AD = 15CM
It has two triangle
Triangle ABC and Triangle ADC
In triangle ABC
Area of ABC = 1/2 × AB ×BC
= (1/2×9×40) CM²
= 180 CM²
In triangle ADC
Area of triangle ADC = 1/2×CD×AD
= (1/2×28×15) CM²
= 210 CM²
Hence, Area of Quadrilateral ABCD = 180 CM²+210CM²
= 390 CM²
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