Math, asked by ramkishor4117, 9 months ago

find the area of the quadrilateral whose vertices are (2,-1),(4,3),(-1,2),(-3,-2) taken in order

Answers

Answered by Himanshu42416

0

Answer:

48 unit^2

Step-by-step explanation:

Diagonal AC is horizontal of length 8.

Vertical distance between B and D is 4x3=12.

Area of quad. => 12x8/2=48^2

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