Math, asked by aswini06, 10 months ago

find the area of the quadrilateral whose vertices are (-3,4) (-5,-6) (4,-1) and (1,2)​

Answers

Answered by kausalya61
4

Answer:

The area of quadrilateral is 23 square units.

Step-by-step explanation:

We are given a quadrilateral ABCD whose vertices are A(-5,-3) B(-4,-6) C(2,-1) D(1,2). Please find attachment for figure.

Using area of triangle of coordinate,

In ΔABD, A(-5,-3) B(-4,-6) D(1,2)

In ΔBCD, C(2,-1) B(-4,-6)  D(1,2)

ar (ABCD) = ar(ABD) + ar(BCD)

ar (ABCD) = 23/2+ 23/2 = 23 square units.

Hence, The area of quadrilateral is 23 square units.

Answered by sriramsunil13
9

Answer:43sq. Units

Step-by-step explanation:

1/2[(18+5+8+4) - (-20-24-1-6)]

1/2 [35+51]

1/2 (86)

43sq. Units

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