Question

find the area of the quadrilateral whose vertices are a(1 ,0) b(7,0) c(6,3) and d(2, 3)​

Answer 1

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Answer 2

The area of quadrilateral whose vertices are A(1,0), B(7,0) , C (6,3) D(2,3) is 15 sq.units .The stepwise explanation is given below:

- we had to find out the area of the quadrilateral ABCD whose vertices are given as :

A(1,0)

B(7,0)

C(6,3)

D(2,3)

- Let ABCD be the given quadrilateral

so, A(x1 ,y1) = A(1,0)

B(x2,y2) = B(7,0)

C(x3,y3) = C(6,3)

D(x4,y4) = D(2,3)

- These are the vertices of the quadrilateral.

- Now the area of quadrilateral can be solved with the help of cross - multiplication method

i.e. 1/2[ (x1×y2 + x2×y3 + x4×y1) - (x2×y1 + x3×y2 + x4y3 + x1×y4) ]

By putting the values we get,

= 1/2 [ (1×0 + 7×3 + 6×3 + 2×0) - (7×0 + 6×0 + 2×3 + 1×3) ]

= 1/2 [ (0+21+18+0) - (0+0+6+3) ]

= 1/2×39-9

= 1/2×30

= 15 sq.units

- So, the area of quadrilateral ABCD is 15s sq.units