Question

Find the area of the quadrilateral whose vertices
taken in order are (-4,-2), (-3,-5), (3 - 2)
and (2,3)




guys pls solve this question and pls don't put unnecessary answers pls it's me request​

Answer 1

Answer:

Area of quadrilateral ABCD = Area of ABC + Area of ACD

Step-by-step explanation:

Let the vertices of the quadrilateral be:

A(-4, -2), B(-3, -5), C(3,-2), D(2, 3)

Joining AC,

There are 2 triangles formed. ABC and ACD

Hence,

Area of quadrilateral ABCD = Area of ABC + Area of ACD

Hope this helps

Answer 2

Step-by-step explanation:

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