Question

find the area of the quadrilaterals whose verticals taken im order are (-4,-2),-3,-5),(3,-2) and {2,3)​

Answer 1

let

(-4,-2)is vertex A

(-3,-5)is vertex B

(3,-2)is vertex C

(2,3)is vertex D

these coordinates form a rectangle on graph

so,

distance of lines

AB is 5unit which is breadth of rectangle.

&

BC is 6 unit which is length of rectangle.

we know that,

area of rectangle = length x breadth

5 unit x 6 unit

${30 \: unit}^{2}$

when you make figure in propre way then the figure is according to answer