find the area of the quadrillateral ABCD
(answer should come 66cm²)
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Answer:
66 sq cm
Step-by-step explanation:
Its simple! {If given that height of both triangles are same}
Divide the quadrilateral in 2 triangles as shown to find the area.
Area of first triangle will be 1/2 x base x height
=1/2 x 11 x 6=33
Similarly, area of 2nd triangle will also be 33
Total area=33+33=66 sq cm
ALTERNATIVE METHOD{If not given that height of both triangles are same}
Let height of first triangle be h1 and height of second triangle be h2
Area of first triangle= 11/2 x h1
Area of second triangle= 11/2 x h2
Total Area= [11/2 x h1] + [11/2 x h2]
= 11/2 [h1+h2]
= 11/2 x 12
11 x 6 = 66 sq cm
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