Question

find the area of the recangle whose length is 12.5cm and breadth is 9m

Answer 1

we know that , area of a rectangle = length × breadth


=> area of rectangle = 12.5 cm × 900 cm

( since , 1 meter = 100 cm
=> 9 meter = 900 cm)

=> area of rectangle = 11250 cm²

or we can write it as , 1.125 m²

hope this helps

Answer 2

$\rule{300}3$

$\huge{\blue{\fbox{\bold{\red{UR\:QUESTION}}}}}$

$\huge {\mathbf {\purple {Q.}}}}$find the area of the recangle whose length is 12.5cm and breadth is 9m

$\rule{300}3$

$\huge{\blue{\fbox{\bold{\red{UR\:ANSWER}}}}}$ ✓

$\Large\bold\purple{given,}$

$\sf\dashrightarrow length\:is\:12.5cm$

$\sf\dashrightarrow breadth\:is\:9m$

$\sf\underline\bold{conveting\:9m\:in\:cm}$

$\tt\implies 1m=100cm$

$\tt\implies 9m= ?$

$\tt\implies 9×100$

$\sf\implies 900cm$

$\tt\underline\bold{length=900cm}$

$\Large\bold\red{to\:find,}$

$\large\implies area\:of\:rectangle$

$\Large\bold\green{diagram,}$

Rectangle

$\setlength{\unitlength}{1.6mm}\begin{picture}(5,6)\put(0,25){\line(1,0){35}}\put(0,0){\line(1,0){35}}\put(0,0){\line(0,1){25}}\put(35,0){\line(0,1){25}}\put(17,-2){900cm}\put(18,-2){}\put(35,15){12.5cm}\put(18,0){ }\end{picture}$

$\Large\underline\bold{solution,}$

$\sf\implies area\:of\:rectangle\:=length×breadth$

$\sf\implies 12.5×900$

$\sf\implies 11,250cm^2$

$\sf{\pink{\fbox{\purple{area\:of\:rectangle=11,250cm^2}}}}$

$\rule{300}3$

$\tt\huge\red{\text{BE \:BRAINLY}}$

$\rule{300}3$